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16s^2+725s+8064=0
a = 16; b = 725; c = +8064;
Δ = b2-4ac
Δ = 7252-4·16·8064
Δ = 9529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(725)-\sqrt{9529}}{2*16}=\frac{-725-\sqrt{9529}}{32} $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(725)+\sqrt{9529}}{2*16}=\frac{-725+\sqrt{9529}}{32} $
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